Integrand size = 25, antiderivative size = 82 \[ \int \frac {1}{(a-i a x)^{5/4} (a+i a x)^{9/4}} \, dx=\frac {2 i}{5 a^2 \sqrt [4]{a-i a x} (a+i a x)^{5/4}}+\frac {6 \sqrt [4]{1+x^2} E\left (\left .\frac {\arctan (x)}{2}\right |2\right )}{5 a^3 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \]
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Time = 0.02 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {53, 48, 42, 203, 202} \[ \int \frac {1}{(a-i a x)^{5/4} (a+i a x)^{9/4}} \, dx=\frac {6 \sqrt [4]{x^2+1} E\left (\left .\frac {\arctan (x)}{2}\right |2\right )}{5 a^3 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}}+\frac {2 i}{5 a^2 \sqrt [4]{a-i a x} (a+i a x)^{5/4}} \]
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Rule 42
Rule 48
Rule 53
Rule 202
Rule 203
Rubi steps \begin{align*} \text {integral}& = -\frac {2 i}{a^2 \sqrt [4]{a-i a x} (a+i a x)^{5/4}}+\frac {3 \int \frac {1}{\sqrt [4]{a-i a x} (a+i a x)^{9/4}} \, dx}{a} \\ & = \frac {2 i}{5 a^2 \sqrt [4]{a-i a x} (a+i a x)^{5/4}}+\frac {3 \int \frac {1}{(a-i a x)^{5/4} (a+i a x)^{5/4}} \, dx}{5 a} \\ & = \frac {2 i}{5 a^2 \sqrt [4]{a-i a x} (a+i a x)^{5/4}}+\frac {\left (3 \sqrt [4]{a^2+a^2 x^2}\right ) \int \frac {1}{\left (a^2+a^2 x^2\right )^{5/4}} \, dx}{5 a \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \\ & = \frac {2 i}{5 a^2 \sqrt [4]{a-i a x} (a+i a x)^{5/4}}+\frac {\left (3 \sqrt [4]{1+x^2}\right ) \int \frac {1}{\left (1+x^2\right )^{5/4}} \, dx}{5 a^3 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \\ & = \frac {2 i}{5 a^2 \sqrt [4]{a-i a x} (a+i a x)^{5/4}}+\frac {6 \sqrt [4]{1+x^2} E\left (\left .\frac {1}{2} \tan ^{-1}(x)\right |2\right )}{5 a^3 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.02 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.83 \[ \int \frac {1}{(a-i a x)^{5/4} (a+i a x)^{9/4}} \, dx=-\frac {i \sqrt [4]{1+i x} \operatorname {Hypergeometric2F1}\left (-\frac {1}{4},\frac {9}{4},\frac {3}{4},\frac {1}{2}-\frac {i x}{2}\right )}{\sqrt [4]{2} a^3 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \]
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Result contains higher order function than in optimal. Order 5 vs. order 4.
Time = 0.22 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.30
method | result | size |
risch | \(\frac {\frac {6}{5} x^{2}-\frac {6}{5} i x +\frac {2}{5}}{\left (x -i\right ) a^{3} \left (-a \left (i x -1\right )\right )^{\frac {1}{4}} \left (a \left (i x +1\right )\right )^{\frac {1}{4}}}-\frac {3 x {}_{2}^{}{\moversetsp {}{\mundersetsp {}{F_{1}^{}}}}\left (\frac {1}{4},\frac {1}{2};\frac {3}{2};-x^{2}\right ) \left (-a^{2} \left (i x -1\right ) \left (i x +1\right )\right )^{\frac {1}{4}}}{5 \left (a^{2}\right )^{\frac {1}{4}} a^{3} \left (-a \left (i x -1\right )\right )^{\frac {1}{4}} \left (a \left (i x +1\right )\right )^{\frac {1}{4}}}\) | \(107\) |
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\[ \int \frac {1}{(a-i a x)^{5/4} (a+i a x)^{9/4}} \, dx=\int { \frac {1}{{\left (i \, a x + a\right )}^{\frac {9}{4}} {\left (-i \, a x + a\right )}^{\frac {5}{4}}} \,d x } \]
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\[ \int \frac {1}{(a-i a x)^{5/4} (a+i a x)^{9/4}} \, dx=\int \frac {1}{\left (i a \left (x - i\right )\right )^{\frac {9}{4}} \left (- i a \left (x + i\right )\right )^{\frac {5}{4}}}\, dx \]
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Exception generated. \[ \int \frac {1}{(a-i a x)^{5/4} (a+i a x)^{9/4}} \, dx=\text {Exception raised: RuntimeError} \]
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Exception generated. \[ \int \frac {1}{(a-i a x)^{5/4} (a+i a x)^{9/4}} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {1}{(a-i a x)^{5/4} (a+i a x)^{9/4}} \, dx=\int \frac {1}{{\left (a-a\,x\,1{}\mathrm {i}\right )}^{5/4}\,{\left (a+a\,x\,1{}\mathrm {i}\right )}^{9/4}} \,d x \]
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